December 12, 2019

523. Continuous Subarray Sum

523. Continuous Subarray Sum

思路和 560. Subarray Sum Equals K 很相近,用HashMap+Prefix Sum做。这里hashmap的key仍然为prefix sum,value是index,这样可以计算是否有两个及以上元素。

class Solution {
    public boolean checkSubarraySum(int[] nums, int k) {
        Map<Integer, Integer> map = new HashMap<>();
        map.put(0, -1);
        int prefixSum = 0;
        for (int i = 0; i < nums.length; i++) {
            prefixSum += nums[i];
            if (k != 0) {
                prefixSum %= k;
            }
            if (map.containsKey(prefixSum)) {
                if (i - map.get(prefixSum) > 1) {
                    return true;
                }
            }
            if (!map.containsKey(prefixSum)) {
                map.put(prefixSum, i);
            } 
        }
        return false;
    }
}
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