November 24, 2019

279. Perfect Squares

279. Perfect Squares

DP. Time = O(n^2), space O(n)

class Solution {
    public int numSquares(int n) {
        int[] dp = new int[n + 1];
        Arrays.fill(dp, n);
        dp[0] = 0;
        for (int i = 1; i <= n; i ++) {
            for (int j = 1; j * j <= i; j++) {
                dp[i] = Math.min(dp[i], dp[i - j * j] + 1);
            }
        }
        return dp[n];
    }
}
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