98. Validate Binary Search Tree
找每个 node 的合理区间。
Time complexity: O(n) since we visit each node exactly once.
Space complexity: O(n) since we keep up to the entire tree.
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public boolean isValidBST(TreeNode root) {
if (root == null) {
return true;
}
return isValidBST(root, Long.MIN_VALUE, Long.MAX_VALUE);
}
public boolean isValidBST(TreeNode root, long minVal, long maxVal) {
if (root == null) {
return true;
}
if (root.val <= minVal || root.val >= maxVal) {
return false;
}
return isValidBST(root.left, minVal, root.val) && isValidBST(root.right, root.val, maxVal);
}
}