March 06, 2019

47. Permutations II

47. Permutations II

class Solution {
    public List<List<Integer>> permuteUnique(int[] nums) {
        List<List<Integer>> res = new ArrayList<>();
        if (nums == null || nums.length == 0) {
            return res;
        }
        Arrays.sort(nums);
        List<Integer> cur = new ArrayList<>();
        boolean[] visited = new boolean[nums.length];
        helper(nums, visited, cur, res);
        return res;
    }
    
    private void helper(int[] nums, boolean[] visited, List<Integer> cur, List<List<Integer>> res) {
        if (cur.size() == nums.length) {
            res.add(new ArrayList<>(cur));
            return;
        }
        
        for (int i = 0; i < nums.length; i++) {
            // 这里重点是如何做去重
            if (visited[i] || i - 1 >= 0 && visited[i - 1] && nums[i] == nums[i - 1]) {
                continue;
            }
            visited[i] = true;
            cur.add(nums[i]);
            helper(nums, visited, cur, res);
            cur.remove(cur.size() - 1);
            visited[i] = false;
        }
    }    
}
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